verilog - What does always block @ (*) means? - Stack Overflow The (*) means "build the sensitivity list for me" For example, if you had a statement a = b + c; then you'd want a to change every time either b or c changes In other words, a is "sensitive" to b c So to set this up: always @( b or c ) begin a = b + c; end But imagine you had a large always block that was sensitive to loads of signals Writing the sensitivity list would take ages In fact
Whats included in a Verilog always @* sensitivity list? I'm a bit confused about what is considered an input when you use the wildcard @* in an always block sensitivity list For instance, in the following example, which signals are interpreted as inputs
Verilog Always block using (*) symbol - Stack Overflow The always @(*) syntax was added to the IEEE Verilog Std in 2001 All modern Verilog tools (simulators, synthesis, etc ) support this syntax Here is a quote from the LRM (1800-2009): An incomplete event_expression list of an event control is a common source of bugs in register transfer level (RTL) simulations The implicit event_expression, @*, is a convenient shorthand that eliminates these
verilog - Use of forever and always statements - Stack Overflow The difference between forever and always is that always can exist as a "module item", which is the name that the Verilog spec gives to constructs that may be written directly within a module, not contained within some other construct initial is also a module item always blocks are repeated, whereas initial blocks are run once at the start of
always #delay begin vs. always begin #delay - Stack Overflow always #2 begin #1; #2 a = ~a; end one statement inside begin end BTW, All of the above applies to event controls as well as delay controls, so the following are all describing equivalent behavior
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